Chemistry, asked by Diya1057, 10 months ago

Explain:-
Rutherford's experiment for the discovery of nucleus.
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Answered by dikshaasinghal
1

Answer:

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Explanation:

Thomson's plum pudding model of the atom had negatively-charged electrons embedded within a positively-charged "soup." Rutherford's gold foil experiment showed that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.

In 1911, Rutherford, Marsden and Geiger discovered the dense atomic nucleus by bombarding a thin gold sheet with the alpha particles emitted by radium. ... From this observation, they concluded that almost all the atomic matter was concentrated in a tiny volume situated at the atome center, the atomic nucleus.

Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.

Answered by Anonymous
28

AnsWer:-

Rutherford's experiment for the discovery of nucleus:-

Rutherford allow fast moving Alpha particle to strike thin gold foil and observed:-

  • Most the Alpha particle passed straight through the gold foil which shows that there is lot of empty space in an atom.
  • Some of the Alpha particle deflect through small angles and some are deflected through large angles which show that there is positive charge at the centre of an atom.
  • Very few Alpha particles rebond on heating which show that nucleus is very dense and hard.

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