Science, asked by aryak27, 1 year ago

explain Rutherford's Scattering Experiment


aryak27: number to bolo
aryak27: yaha pe batao
aryak27: bol yaha kuch nahi hoga
pariharmahendrasingh: hi aryak

Answers

Answered by sahi2345
28
Conclusion of Rutherford's scattering experiment: Most of the space inside the atom is empty because most of the α-particles passed through the gold foil without getting deflected. 

hope it helps to u buddy

mark as brainiest if u can
Answered by simpl3737
19
Rutherford bombarded a thin sheet of gold (of 0.00004 cm) with Alpha particles in an evacuated chamber.

Alpha particle is 4 times heavier as heavy as hydrogen atom and has two unit of positive charge .They are represented by Helium nuclei,as He2+. They are emitted by Radioactive elements .

OBSERVATIONS:

1)Most of the Alpha particles (nearly 99%) passed Straight Through the foil without any deflection from their path.

2)A small fraction of Alpha particles (about 1 in every 20,000) were deflected from their original path by small angles .

3)Only a few Alpha particles (about 1 in one million) almost bounced
back .

Rutherfod made following CONCLUSIONS :

1)Since most of the Alpha particles passed through the foil undeflected it indicates that most of the space in an atom is empty .

2)Alpha particles being positively charged and having considerable mass could be deflected by some heavy positively charged centre .

3)Bouncing back of Alpha particles indicated that positively charged Centre is rigid and any Alpha particle making head on collision is that deflected through large angle or bounced back .
Attachments:
Similar questions