explain second law of motion and hence driver f = Ma
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Newton’s second law of motion states that: the net external force applied on an object is directly proportional to the rate of change of linear momentum of the object.
Derivation
velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
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