Physics, asked by srihari890, 2 months ago

Explain Stefan's law of Radiation?

Answers

Answered by ashokkumarchaurasia
1

Explanation:

Stefan-Boltzmann law, statement that the total radiant heat power emitted from a surface is proportional to the fourth power of its absolute temperature. The law applies only to blackbodies, theoretical surfaces that absorb all incident heat radiation.

Answered by ITZBFF
2

Stefan's law :- Stefan's law states that the emissive power of a black body is directly proportional to the fourth power of its absolute temperature.

 \boxed{ \boxed{ \sf \purple{i.e, \:  E \propto {T}^{4}}}}

 \sf{i) \: for \: a \: black \: body \:  -  -  >  \: i.e, E  =  \sigma {T}^{4}} \:  \:( where \:  \sigma \:  = stefan's \:  law )

 \sf{ii) \: for \: any \: body \:  -  -  >  \: i.e, E   = e  \sigma {T}^{4}} \:  \:( where \:  e \: i s \:  emissivity)

 \boxed{ \boxed{ \sf \sigma \:  =  \: stefan's  \: constant \:  = 5.67 \times  {10}^{ - 8} W \:  {m}^{ - 2}  \: K ^{ - 4} }} \\

 \sf{It  \: depends  \: on \:  the \:  nature \:  of \:  surface  \: of  \: the  \: body. }

 \sf{Its  \: value  \: ranges \:  from \:  0 \:  to  \: 1}

 \sf \purple{For \:  a \:  black  \: body, } \sf{e=1 \:  and \:  for \:  a  \: perfect \:  reflector,  \: e=0}

 \boxed{ \boxed{Emissive \:  power  \: (E) = \frac{radiating \: power \: (P)}{surface \: area \: of \: the \: body \: (A)}}} \\

 \sf{E = \frac{P}{A} \implies \frac{P}{A} = e \sigma {T}^{4}} \\

 \boxed{ \boxed{ \sf{Radiating \:  power \:  (P) = e \sigma A {T}^{4}}}}

Similar questions