Question

explain step by step​

Answer 1

Answer:

$\bold\red{169}$

Step-by-step explanation:

Let the number is k

Now,

to find the smallest positive number which leaves remainder 1 when divided by each of 6, 7 and 8.

Find the LCM of 6, 7 and 8

The LCM of 6, 7 and 8 is 168.

( Refer to the attachment )

Since, the number 168 is divisible by each of 6,7 and 8.

But,

we need that number which leaves remainder 1 on divided by each of 6, 7 and 8.

Therefore,

the required number = (168 + 1)

Hence,

k = 169

Answer 2

Answer:

Step-by-step explanation:

the LCM of 6,7,8 is 168

by adding 1 to the LCM of 6,7,8

we get 169 as the answer which gives 1 as reminder when divided by 6,7,8

because by the abruation it self  it is least common factor