Math, asked by jiwanthakur78, 3 months ago

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Answered by BrainlyMind813
3

Answer:

4 \: is \: the \: value \: of \: x \:  -  \:   \frac{1}{x}

Step-by-step explanation:

  \: ({x \:  -  \:  \frac{1}{x} })^{2}  \:  =  {x}^{2}  +  \frac{1}{ {x}^{2} }  - 2  =  \: 18

using \:  \: ( {a} -  \:  {b})^{2}  =  \:  {a}^{2}  +  {b}^{2}  -  \: 2ab \:

 \: ( x \: -  \frac{1}{x} )^{2}  =  \: 16

( x \:  -  \: \frac{1}{x} ) =  \sqrt{16}

 \: (x -  \frac{1}{x} ) = 4

Hope this answer helped you out, have a nice day

Answered by vashushubu77
5

4 \: is \: the \: value \: of \: (x− \frac{1}{x} )............ \\  \\  \\  (x− \frac{1}{x} )^{2} = \: x^{2} +  \frac{1}{ {x}^{2} }   \: − \: 2=18 \:  \\ using \: (a−b)^{2}  =a^{2} + {b}^{2} −2ab \\ (x− \frac{1}{x} )^{2} =16.......(x−\frac{1}{x} )= \sqrt{16}  \\ (x  \: - \:  \frac{1}{x} ) = 4

MARK BRAINLEIST...

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