Math, asked by frustratedinsaan1909, 11 days ago

explain step by step​

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Answered by XxFAKELOVExX
13

 \frac{2}{ \sqrt{3 +  \sqrt{5} } }  +  \frac{5}{ \sqrt{3} -  \sqrt{5}  }

 \frac{2}{ \sqrt{3}  +  \sqrt{5}  }  =   \frac{ \sqrt{3}   - \sqrt{5} }{ \sqrt{3} -  \sqrt{5}  }  +   \frac{5}{ \sqrt{3} -  \sqrt{5}  }  =  \frac{ \sqrt{3}  +  \sqrt{5} }{ \sqrt{3 +  \sqrt{5} } }

 \frac{ - (2 \sqrt{3} - 2 \sqrt{5})  }{2}  +  \frac{ -( 5 \sqrt{3} + 5 \sqrt{5})  }{2}

 \frac{ - 2 \sqrt{3} + 2 \sqrt{5}  }{2}    \frac{ - 5 \sqrt{3} - 5 \sqrt{5}  }{2}

 \frac{ - 2 \sqrt{3} + 2 \sqrt{5} - 5 \sqrt{3}   - 5 \sqrt{5}  }{2}

 \frac{ - 2 \sqrt{3} - 5 \sqrt{3} + 2 \sqrt{5}  - 5 \sqrt{5}   }{2}

 \frac{ - 7 \sqrt{3} - 3 \sqrt{5}  }{2}

 \frac{ - 7 \sqrt{3} }{2}   \frac{ - 3 \sqrt{5} }{2}

a =  \frac{ - 7}{2}

b \:  =  \frac{ - 3}{2}

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