Math, asked by dheerajmehta20p6px9c, 10 months ago

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Answered by arpi1401
3

Answer:

x= 3

put the value of x

k square (3)cube - k(3) square+ 3k(3) - k = 0

27ksquare - 9k + 9k - k= 0

27k square - k = 0

27k square= k

1/27 = k square/ k

1/27 = k

hence, value of k is 1/27.......


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Answered by anujyadav3124
3

Answer:

x = 3. \\   {k}^{2}  {x}^{3}  - k {x}^{2}  + 3kx - k \\  {k}^{2}( {3}^{3} ) - k {3}^{2}  + 3k \times 3 - k \\ 27 {k}^{2}  - 9k + 3k - k \\  27 {k}^{2}  - 6k - k \\ 27 {k}^{2}  - 7k.

here is your answer

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