Question

explain stoke,s law.................​

Answer 1

Answer:

In 1851, George Gabriel Stokes derived an expression, now known as Stokes law, for the frictional force – also called drag force – exerted on spherical objects with very small Reynolds numbers in a viscous fluid.

In 1851, George Gabriel Stokes derived an expression, now known as Stokes law, for the frictional force – also called drag force – exerted on spherical objects with very small Reynolds numbers in a viscous fluid.Formula

F=6 \pi r \eta v

F = drag force

π = pi

= pir = sphere radius

= pir = sphere radius\eta = fluid viscosity

= pir = sphere radius\eta = fluid viscosityv = velocity of the sphere

Answer 2

Explanation:

F=6πnrv

according to stokes law

fluid friction on sphre falling through a liquid is given by F=6πnrv

where

f is fluid friction

n is coefficient of viscosity

r i

r is radius of sphere

and v is terminal velocity