Question

explain Swartz reaction with example​

Answer 1

Answer:

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Answer 2

"Swartz reaction is generally used to get alkyl fluorides from alkyl chlorides or alkyl bromides. "

• This can be done by heating the alkyl chloride/bromide in the existence of the fluoride of any heavy metal like silver fluoride. The reaction will process if sodium fluoride is used, but the resulting yield will be significantly lower.
• In the Swartz fluorination reaction, chlorine is commonly replaced by fluorine in organic compounds with the help of a trifluoride in the presence of some salts where the oxidation state is +5.
• The reaction procedure is that the metal fluorine bond is broken and a new bond is formed between carbon and fluorine. The displaced chlorine atom now bonds with the metal. The mixture of trifluoride and chlorine is known as the Swartz reagent.
• Swartz rule states that post fluorination, the fluoride formed will always have a lower boiling point than the corresponding chloride.
• The examples of a Swartz reaction are :
  $CCl_{4}$ → $CF_{2} Cl_{2} +CHCl_{3}$
  $CHCl_{3}$ → $CHFCl_{2} + CHF_{2}Cl$

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