Explain 'tan O' interms of sin 10. The n'h term of A.P is a If a, +2, + a, = 102 and a, = 15, then find a 109
Answers
Answered by
0
The nth term of A.P is a_{10}a
10
= 216
Explanation:
n + n term = a_{n}a
n
= a+(n-1)d
a→ 1st term
d → common difference
a_{1}a
1
= a = 15
a_{2}a
2
= a+d = 15+d
a_{3}a
3
= a+2d = 15+2d
a_{1}a
1
+a_{2}a
2
+a_{3}a
3
= 102
15+15+d+15+2d = 102
3d = 102-45 = 67
d=67/3
a_{10}a
10
= a+(10-1)d
= a+2d
= 15 + 2 × \frac{67}{3}
3
67
= 15 + 201
= 216
Hence = a_{10}a
10
= 216
To learn more...
If a1,a2,a3,..are in ap such that a1+a5+a10+a15+a20+a24=225, then a1+a2+a3+..a23+a24
A1, a2, a3,..a24 are in A.P. and a1+a5+a10+a15+a20+a24=300. find the sum of first 24 terms of A.P.
Similar questions