Math, asked by gautampopli, 6 months ago

Explain Taylor's theorem of Expending function.​

Answers

Answered by Anonymous
1

Answer:

In calculus, Taylor's theorem gives an approximation of a k-times differentiable function around a given point by a polynomial of degree k, called the kth-order Taylor polynomial. ... Taylor's theorem is taught in introductory-level calculus courses and is one of the central elementary tools in mathematical analysis

Answered by hkofficial654
0

Step-by-step explanation:

In calculus, Taylor's theorem gives an approximation of a k-times differentiable function around a given point by a polynomial of degree k, called the kth-order Taylor polynomial. For a smooth function, the Taylor polynomial is the truncation at the order k of the Taylor series of the function. The first-order Taylor polynomial is the linear approximation of the function, and the second-order Taylor polynomial is often referred to as the quadratic approximation.[1] There are several versions of Taylor's theorem, some giving explicit estimates of the approximation error of the function by its Taylor polynomial.

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