Math, asked by djdj132, 1 year ago

explain terminal velocity

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Answered by fanbruhh
65

 \huge{hey}


 \huge { \mathfrak{here \: is \: answer}}


 \bf{terminal \: velocity}


<b> when a solid spherical ball free falling in any viscous liquid viscous force acts upon it in upward direction according to stock according to archimides principle buoyant force also acts on the body in upward direction due to this the  velocity of a spherical ball decrease and when net force acting upon a spherical ball is zero spherical ball moves with a constant velocity and this velocity is known as terminal velocity.</b>


<I> force acting on a spherical ball</I>


 see \: in \: pic

 \huge \bf \boxed {hope \: it \: helps}

 \huge{ \mathbb{THAnks}}

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Answered by Anonymous
63

Answer:here your answer

Step-by-step explanation:

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