Question

Explain thad question a train accelerates from 36 km/h to 54/ in 10 sec

Answer 1

AnswEr :

Given that a train accelerates from 36 km/h to 54 km/h in 10 seconds.

We have to find acceleration of train.

What is acceleration?

Acceleration is rate of change in velocity/speed. Acceleration is given by,

Division of (difference b/w initial & final velocity/speed) and time.

Acceleration = (v - u)/t

From the given data :

Initial speed = 36 km/h

→ Initial speed = 36 × (5/18) m/s

→ Initial speed = 10 m/s

And, final speed = 54 km/h

→ Final speed = 54 × (5/18) m/s

→ Final speed = 15 m/s

Time (t) = 10 seconds.

From the first equation of motion i.e. v = u + at,

Substituting values,

→ 15 = 10 + a × 10

→ 15 = 10 + 10a

→ 15 - 10 = 10a

→ 5 = 10a

→ a = 5/10

→ a = 0.5 m/s²

∴ Acceleration of train = 0.5 m/s² (Ans.)

Answer 2

Given :-

• Initial velocity =36km/h=36×5/18=10m/s

• Final velocity =54km/h=54×5/18=15m/s

• Time taken =10s

To Find:-

• Acceleration (a) of train

Solution :-

By using 1st equation of motion

➦ v=u+at

➭ 15=10+a×10

➭ 15-10=a×10

➭ a = 5/10

➭ a = 0.5m/s²

∴The acceleration of train is 0.5 m/s².

Extra Information!!!!!!!

☛ The rate of change of velocity at per unit time is called acceleration .

☛ SI unit of acceleration is m/s²

☛ It is vector quantity.