Question

Explain the Acceleration of free fall ?​

Answer 1

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It was learned in the previous part of this lesson that a free-falling object is an object that is falling under the sole influence of gravity. A free-falling object has an acceleration of 9.8 m/s/s, downward (on Earth). The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s.

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Answer 2

its a complicated question to me because i read this in class 8th so complicated because i remembered or not but i remember so its very interesting plus little tough for new lerner if u read this twice ot thrice u will get this exactly lets begin

ACCELERATION OF FREE FALL:

a free fall object has an acceleration of 9.8m/s/s(meter per second square)on the earth

the numerical value for the acceleration free fall object is such important value it gives a special name the uniform formula can be used when dealing with free fall acceleration due to gravity is 9.8m/s2(this value is often taken to be 10m/s2 for convenience

• free falling bodies undergo constant acceleration
• such motion is referred as free fall
• the free fall acceleration is denotes as with symbol small g (g)

at the surface of the earth the magnitude of g is in approx 9.8 m/s2(meter per seconds square)

FREE FALL EQUATIONS KEY:

• Vv (vertical velocity) in (m/s) (meter per second)
• Dv (vertical distance) in meter
• g acceleration due to gravity (10 m/s2)
• t time (in second)

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