Question

explain the acid-base reaction of liquid sulphur dioxide​

Answer 1

Answer:

The balanced reaction is given below:

2SO2+O2+2H2O→2H2SO4

5.6        4.8                         (No. of moles given)

25.6    14.8                    (Ratio of moles given and stoichiometry coefficient )   

=2.8     =4.8 

As 2.8 is lower than 4.8, SO2 is the limiting reagent and product will form according to number of moles of SO2 (given).

So, moles produced of H2SO4=22×5.6=5.6 mol.

Explanation:

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