Explain the action of dilute hydrochloric acid on the following with chemical equestion 1 magnesium ribbon 2 sodium hydroxide 3 crushed egg sheels
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Answered by
104
Answer:
1- HCl + Mg -- MgCl2 + H2
2- HCl + NaOH ---NaCl + H2o
3- HCl + CaCo3 --CaCl2 + H2O + Co2
Answered by
48
Answer:Reaction of hydrochloric acid with magnesium ribbon.
In this reaction hydrochloric acid react with magnesium ribbon and form magnesium chloride and hydrogen gas.
2HCl+ Mg =========》 MgCl2 +H2
✴Reaction of hydrochloric acid with sodium hydroxide.
HCl+ NaOH ========》NaCl + H2O
that is when hydrochloric acid react with Sodium Hydroxide it leads to the formation of the salt sodium chloride and water.
✴Reaction with crushed egg cell.
2HCl+ CaCO3 ========》CaCl2 + CO2 + H2O
when hydrochloric acid reacts with crushed egg shells and utilise to you formation of calcium chloride carbon dioxide gas and water.
Explanation:
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