Chemistry, asked by divadbhat, 9 months ago

Explain the action of dilute hydrochloric acid on the following with chemical equation: (i) Magnesium ribbon (ii) Sodium hydroxide (iii) Crushed egg shells

Answers

Answered by sins007
13

(1) Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g) This demonstration can be used to illustrate the characteristic reaction of metals with acid

when acid and metal reacts it forms salt and Hydrogen as

Explanation:

(2) acid and base produce __ salt and water

Hydrochloric acid reacts with sodium hydroxide to form sodium chloride (the salt) and water. Sodium chloride is made up of Na+ cations from the base (NaOH) and Cl- anions from the acid (HCl). HCl+NaOH→H2O+NaCl.

(3) egg shell is a base so the same reaction as above will take place __ acid and base produce __ salt and water

Egg shell contains calcium carbonate. When HCl is poured over egg shells, it dissolves in HCl to form calcium chloride and water and carbon dioxide is liberated with effervescence.

Answered by ansh65932
9

Explanation:

(i)Mg+2HCl=MgCl2+H2

(ii)NaOH+HCl=NaCl+H2O

(iii)CaCO3+HCl=CaCl2+H2O+CO2

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