Question

explain the action of dilute hydrochloric acid on the following chemical reaction a) magnesium ribbon b) sodium hydroxide 3)crushed egg shell​

Answer 1

(i) Mg + 2HCI → MgCl2 + H2 Hydrogen gas is produced.

(ii) HCl + NaOH→ NaCl + H2O Neutralisation reaction

(iii) 2HCl(aq) + CaCO3(s)→CaCl2 (aq)+ H2O + CO2 Calcium chloride is formed.

Detailed Answer:

(i) Dilute hydrochloric acid reacts with magnesium to form magnesium chloride and H2 gas is liberated. Mg(s) + 2HCl(aq)→MgCl2(aq) + H2(g)

(ii) sodium hydroxide is a neutralisation reaction. Sodium chloride salt and water are formed,Reaction between dilute hydrochloric acid and NaOH(aq) + HCI(aq)→NaCl(aq) + H2O(l)

(iii) Dilute hydrochloric acid dissolves the CaCO3 and makes the shell soft.Egg shells are made of calcium carbonate, CaCO3. CaCO3(s) + HCI(aq)→ CaCl2 + CO2(g) + H2O(l) (Crushed egg shell)

Answer 2

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