Explain the action of dilute hydrochloric acid on the following with chemical equation.
(a) Magnesium ribbon
(b) Sodium hydroxide
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9
Answer:
(i) Dilute hydrochloric acid reacts with magnesium to form magnesium chloride and H2 gas is liberated.
Mg(s) + 2HCl(aq)→MgCl2(aq) + H2(g)
(ii) sodium hydroxide is a neutralisation reaction. Sodium chloride salt and water are formed,Reaction between dilute hydrochloric acid and
NaOH(aq) + HCI(aq)→NaCl(aq) + H2O(l)
Mujhe jo mila Google mei mila .. wohi copy paste kr diya ... Sorry
Answered by
2
Answer:Sodium hydroxide
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