Question

Explain the action of dilute hydrochloric acid on the following with chemical equation:
(i) Magnesium ribbon (ii) Sodium hydroxide (iii) Crushed egg shells​

Answer 1

Answer:

(i) Mg + 2HCI → MgCl2 + H2 Hydrogen gas is produced. (ii) HCl + NaOH→ NaCl + H2O Neutralisation reaction (iii) 2HCl(aq) + CaCO3(s)→CaCl2 (aq)+ H2O + CO2 Calcium chloride is formed. Detailed Answer: (i) Dilute hydrochloric acid reacts with magnesium to form magnesium chloride and H2 gas is liberated. Mg(s) + 2HCl(aq)→MgCl2(aq) + H2(g) (ii) sodium hydroxide is a neutralisation reaction. Sodium chloride salt and water are formed,Reaction between dilute hydrochloric acid and NaOH(aq) + HCI(aq)→NaCl(aq) + H2O(l) (iii) Dilute hydrochloric acid dissolves the CaCO3 and makes the shell soft.Egg shells are made of calcium carbonate,

Answer 2

Answer:

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