Question

Explain the action of dilute hydrochloric acid on the following with chemical equations:
i) magnesium ribbon
ii)sodium hydroxide
iii)curshed egg shells.

Answer 1

Hi dear.....


Here is ur ans.....


1) HCl + Mg (s) ------------> MgCl2 + H2



2) HCl. + Na( OH)-------------->NaCl + H2O



3 ) HCl + CaCo2 ----------> Ca(OH)2 + Co2 + H2



Hope it hlps...

Have a good day dear....

☺☺☺☺☺

Answer 2

Heya!!Here is your answer friend ⤵⤵
↔↔↔↔↔↔↔↔↔↔↔↔↔↔


⏪Explain the action of Hydrochloric acid (HCL) ON the following with chemical equations .


(1). Magnesium ribbon

⏪. Mg. + HCl -------------MgCl2 +. H2⬆

↔It is an example of reaction between an acid and a metal which produces a metal salt and HYDROGEN gas is evolved.


(2). Sodium hydroxide

⏪ NaOH + HCl-----------NaCl + H2O

↔It is a neutralization reaction i,e a reaction between an acid and a base . This produce a metal salt and water respectively.Hope

(3). Crushed egg shells .

⏪ CaCO3+. HCl-----------CaCl2. + CO2. + H2O

↔It is a example of reaction between an acid and a metal carbonate . It produces a corresponding metal salt, carbon dioxide and water as products .


↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔↔



Hope it helps you ✌✌☺☺