Science, asked by ŸuvïŸáÄr, 1 year ago

Explain the action of dilute hydrochloric acid with chemical equations .1 magnesium ribbon. 2 sodium hydroxide. 3 crushed egg shell

Answers

Answered by gautam96
793
Reactions of hydrochloric acid with magnesium ribbon ,sodium hydroxide and crushed egg shell.
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✴Reaction of hydrochloric acid with magnesium ribbon.

In this reaction hydrochloric acid react with magnesium ribbon and form magnesium chloride and hydrogen gas.

2HCl+ Mg =========》 MgCl2 +H2

✴Reaction of hydrochloric acid with sodium hydroxide.


HCl+ NaOH ========》NaCl + H2O

that is when hydrochloric acid react with Sodium Hydroxide it leads to the formation of the salt sodium chloride and water.


✴Reaction with crushed egg cell.

2HCl+ CaCO3 ========》CaCl2 + CO2 + H2O
when hydrochloric acid reacts with crushed egg shells and utilise to you formation of calcium chloride carbon dioxide gas and water.
Answered by ajisha1980
195

Answer:

Reaction of hydrochloric acid with magnesium ribbon.

In this reaction hydrochloric acid react with magnesium ribbon and form magnesium chloride and hydrogen gas.

2HCl+ Mg =========》 MgCl2 +H2

Reaction of hydrochloric acid with sodium hydroxide.

HCl+ NaOH ========》NaCl + H2O

that is when hydrochloric acid react with Sodium Hydroxide it leads to the formation of the salt sodium chloride and water.

Reaction with crushed egg cell.

2HCl+ CaCO3 ========》CaCl2 + CO2 + H2O

when hydrochloric acid reacts with crushed egg shells and utilise to you formation of calcium chloride carbon dioxide gas and water.

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