Question

Explain the action of dilute hydrochloride acid on the following with chemical equations :
A . Magnesium ribbon
B. Sodium hydroxide
C. Crushed egg shell

Answer 1

magnesium ribbon = Mg(magnesium)
sodium hydroxide = NaOH
crushed egg shell = CaCO3
hydrochloride acid or hydrochloric acid = HCl

A)Mg + 2HCl--->MgCl2 + H2
B)NaOH + HCl--->NaCl + H2O
C)CaCO3 + 2HCl--->CaCl2 + H2CO3

  :)hope this ans would help u....

Answer 2

)Mg + 2HCl--->MgCl2 + H2
B)NaOH + HCl--->NaCl + H2O
C)CaCO3 + 2HCl--->CaCl2 + H2CO3