Question

Explain the action of dilute sulphuric acid on the following with chemical equation:

i. Magnesium ribbon ii. Sodium Hydroxide iii. Crushed egg shells​

Answer 1

Answer:

(i)When you contact magnesium metal with an aqueous solution of hydrochloric acid (HCl and H2O) you will get dissolved magnesium chloride and hydrogen gas. Mg(solid) + 2HCl (aqueous) => H2(gas) + MgCl2 (aqueous) (ii)There is no noticable change in the appearance of the solution, it remains colourless like water. There is some heat of reaction, which you may not notice in dilute solutions HCl + NaOH => NaCl + H2O + heat (iii)Egg shells are just the same as marble , they contain calcium carbonate CaCO3. So when u react CaCO3 with HCl.If there is enough hydrochloric acid in the container, the egg shells completely dissolve. CaCO3 + HCl — CaCl2 + H20 + C02

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Answer 2

Answer:

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