Chemistry, asked by sharafat9518755356, 2 months ago

explain the action of the following carbolic acid. 1) bromine water 2) conc.nitric acid 3) conc.sulphuric acid and room temperature.​

Answers

Answered by makshamsi237
0

Answer:

acid right answers I am a geinus

Answered by preeti353615
0

Answer:

Reaction mention below

Explanation:

Action of bromine water on carbolic acid (phenol): Phenol when treated with bromine water at low temperature forms 2,4,6-tribromophenol.

Dillute nitric acid : When phenol is treated with dilute nitric acid, a mixture of o-nitrophenol and p-nitrophenol (major) is formed. In this reaction, p-nitrophenol is formed as the major product.

H_2SO_4 at room temperature on phenol: At 298 K, phenol reacts with conc. H_2SO_4 forming o-phenol sulphonic acid as major product.

Attachments:
Similar questions