Question

explain the answer please it's urgent​

Answer 1

Answer:

kindly check the attachment

Answer 2

Step-by-step explanation:

Given :-

2t-(3t+6)-6(2-3t) = 2(3+5t)-3(2t-5)

To find :-

Find the value of t ?

Solution :-

Given equation is

2t-(3t+6)-6(2-3t) = 2(3+5t)-3(2t-5)

=> 2t-3t-6-12+18t = 6+10t-6t+15

=> (2t-3t+18t)+(-6-12) = (10t-6t)+(6+15)

=> (20t-3t)+(-18) = (4t)+(21)

=> 17t-18 = 4t+21

=> 17t-4t = 21+18

=> 13t = 39

=> t = 39/13

=> t = 3

Therefore, t = 3

Answer :-

The value of t for the given problem is 3

Check:-

If t = 3 then LHS

=> 2t-(3t+6)-6(2-3t)

=> 2(3)-(3×3+6)-6(2-3×3)

=> 6-(9+6)-6(2-9)

=> 6-15-6(-7)

=> 6-15+42

=> 48-15

=> 33

LHS = 33

and RHS = 2(3+5t)-3(2t-5)

=> 2(3+5×3)-3(2×3-5)

=> 2(3+15)-3(6-5)

=> 2(18)-3(1)

=> 36-3

=> 33

=> RHS = 33

LHS = RHS is true for t = 3