Explain the bond angle trend in the following moecules
CH4
NH3
H2O
Answers
Answered by
0
Answer:
ssmsjsjsjssnsjxhzjsmalalaljzbxbx so sorry I don't know
Answered by
0
Answer:ln ch4 the carbon atom has 4 bond pairs .so bp-bp repulsion occurs to equal extent thereby assigning it a regular tetrahedral geometry.
In ammonia, the central atom has 1 lp and 3 bp so to get rid of this repulsion the H-N^-H bond angle reduces from 109.5°to 107°3'.therefore NH3 adopts a pyramidal shape
Explanation:pls mark it as the brainliest
Similar questions