Question

explain the bond angles in H2O and NH3 on the basis of valence Bond theory ​

Answer 1

Answer:

As a result, the lone pair of electrons will repel another pair strongly. Therefore three N–H bonds of NH3 are forced slightly closer. This leads to decrease in H – N – H bond angles from a normal angle of a tetrahedron (109.5°) to 107°. The most favourable arrangement is distorted tetrahedral i.e. pyramidal.

Answer 2

Answer:

has six electrons in the valence shell. Two of these electrons are mutually shared with the electrons of two hydrogen atoms to form two O - H bonds. ... The lone pairs repel the bond pairs more effectively resulting in the decrease of H – O – H angle from 109.5° to 104.5°.