Question

explain the bond formation in Nacl​

Answer 1

Answer:

Ionic bonds form when atoms transfer electrons between each other, forming ions that are electrically attracted to each other forming a bond between them. Sodium chloride (NaCl) is a typical ionic compound. ... Sodium has 1 electron in its outermost shell, and chlorine has 7 electrons.

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Answer 2

$\huge \sf Answer : -$

Bond formation in Sodium Chloride (NaCl)

NaCl is an ionic solid.

The general electronic configurations are...

Na−1S 2 2S 2 2P 6 3S 1

Cr−1S 2 2S 2 2P 6 3S 2 3P 5

Na is in excess of one electron to attain octet configuration.

Cl has one electron less to attain octet configuration.

So, the excess one electron is transferred to a chlorine atom from Na(sodium) atom and thus an ionic bond is formed due to the transfer of electrons. Chloride being a mole electronegative atom than sodium tends to attract the shared electron pair towards itself.

Thus NaCl has Na + and Cl − atoms. Na + −Cl −

Chloride attains octet configuration by gaining on the electron.

Sodium attains octet configuration by losing the electron.

Thus Ionic solid NaCl is stable.