explain the correct order of IP2 of C,N ,O, and F ?
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solution.
Ip2= C < N< F < O
for removal of an e from a cation Ip2= is required .
C + (5e-) = 1s^2 , 2s^2 , 2P1
N+ ( 6e-) = 1S^2 , 2S^2 , 2P^2
O+ ( 7e - ) = 1S^2 , 2S^2 , 2P^3 = >half filled configuration.
F + (8e-) = 1s^2 , 2S^2 , 2P ^4.
Also size = > F+ < N+
be brainly
Ip2= C < N< F < O
for removal of an e from a cation Ip2= is required .
C + (5e-) = 1s^2 , 2s^2 , 2P1
N+ ( 6e-) = 1S^2 , 2S^2 , 2P^2
O+ ( 7e - ) = 1S^2 , 2S^2 , 2P^3 = >half filled configuration.
F + (8e-) = 1s^2 , 2S^2 , 2P ^4.
Also size = > F+ < N+
be brainly
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