Question

explain the derivation of centripetal formula

Answer 1

The force of a moving body is given as

F = ma........(1)

From the figure, we can write the expression

PQ→PQ→ + QS→QS→ = PS→PS→

-v1v1 + v2v2 = ΔvΔv

ΔvΔv = v2v2 - v1v1

The triangle AOB and PQS are similar. So

ΔvABΔvAB = vrvr

AB = arc  AB = vΔΔ t

ΔvvΔtΔvvΔt = vrvr

ΔvΔtΔvΔt = v2rv2r

a = v2rv2r

Substitute this value in (1) we get the centripetal force

F = mv2rv2r = mrω2



hope this helps....
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Answer 2

when a body moves in a circular path then a force acting on the body towards the center is known as centripetal force.
we know F=ma
= >F=mv.v/R
= > F=m(omega)(omega)R
omega=2(pie)n
F=mR(2(pie)n)²
F=4pie²mRn²