Question

explain the derivation of second law....
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Answer 1

Answer:

Newton's second law of motion states that the acceleration of a system is directly proportional to and in the same direction as the net external force acting on the system, and inversely proportional to its mass. In equation form, Newton's second law of motion is a=Fnetm a = F net m .

Explanation:

can be frnd

Answer 2

$Derivation \: of \: Newton's \: third \: law \: of \: motion. \\\: from \: Newton's \: second \: law \: of \: \: motion \\ \\ Consider \: an \: isolated \: system \: of \: two \: bodies \: A \: and\: B \\ \: mutually \: interacting \: with \: each \: other, \: provided \: there \\ is \: no \: external \: force acting \: on \: the \: system. \\ \\ Let \: F_{AB}, be \: the \: force \: exerted \: on \: body \: B \: by \: body \: A \: and \\ \: F_{BA} \: be \: the \: force \: exerted \: by body \: B \: on \: A. \\ Suppose \: that \: due \: to \: these \: forces \:F_{AB} \: and \:F_{BA}, \frac{dp_1}{dt } \\ \: and \: \frac{dp_2}{dt} \: be \: the \: rate \: of \: the \: change \: of \: momentum \: of \\ \: these \: bodies \: respectively. - \\ (i) \: Then, \\ F_{BA} = \frac{ dp_1}{dt }-(i) \\ F_{AB} = \frac{dp2}{dt}- (ii) \\ \blue{ \underline{Adding \: equations \: (i) \: and \: (ii)}} \\ we \: get, \: F_{BA }+ F_{AB} = \frac{dp_1}{dt} + \frac{dp_2}{dt} \\ F_{BA} + F_{AB} = \frac{d(p_1 + p_2)}{dt} \\ If \: no \: external \: force \: acts \: on \: the \: system, \: \\ then, \:\frac{d(p1 + p2)}{dt }= O \\ F_{BA} + F_{AB} = 0 \\ F_{BA} = - F_{AB}- (ii) \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$