Explain the Electric Field due to a Dipole (on its axis) and derive an expression for it.
Answers
Answered by
5
Refer to the attachment !!
Hope it helps !!
:)
Attachments:
Answered by
7
Answer:
Let the point P be at distance r from the centre of the dipole on the side of the charge q, as shown in Fig. (a). that is, it is a vector whose magnitude is charge q times the separation 2a (between the pair of charges q, –q) and the direction is along the line from –q to q.
hope it helps
Similar questions