explain the equation f = MA
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Answered by
7
Hii.. Your answer
According to Newton's second law of motion force is directly proportional to mass and force is directly proportional to acceleration.
F is directly proportional to a
And F Is directly proportional to m
F is directly proportional to m. a
F=k. m. a
Where k=1
F=m.a
According to Newton's second law of motion force is directly proportional to mass and force is directly proportional to acceleration.
F is directly proportional to a
And F Is directly proportional to m
F is directly proportional to m. a
F=k. m. a
Where k=1
F=m.a
Answered by
28
» Force is the proportional the product of mass and acceleration.
hence
=> Force directly proportional to m^P.a^Q
=> F directly proportional m^P.a^Q

» Substitute Dimension formula :-
![= > [ {M}^{1} {L}^{1} {T}^{ - 2} ] = [ {M}^{} ] {}^{P} {[l {t}^{ - 2} ]}^{Q} \\ \\ = > [ {M}^{1} {L}^{1} {T}^{ - 2} ] = [ {M}^{P} {l}^{Q} {t}^{ - 2Q} ] \\ \\ = > [ {M}^{1} {L}^{1} {T}^{ - 2} ] = [ {M}^{} ] {}^{P} {[l {t}^{ - 2} ]}^{Q} \\ \\ = > [ {M}^{1} {L}^{1} {T}^{ - 2} ] = [ {M}^{P} {l}^{Q} {t}^{ - 2Q} ] \\ \\](https://tex.z-dn.net/?f=+%3D+%26gt%3B+%5B+%7BM%7D%5E%7B1%7D+%7BL%7D%5E%7B1%7D+%7BT%7D%5E%7B+-+2%7D+%5D+%3D+%5B+%7BM%7D%5E%7B%7D+%5D+%7B%7D%5E%7BP%7D+%7B%5Bl+%7Bt%7D%5E%7B+-+2%7D+%5D%7D%5E%7BQ%7D+%5C%5C+%5C%5C+%3D+%26gt%3B+%5B+%7BM%7D%5E%7B1%7D+%7BL%7D%5E%7B1%7D+%7BT%7D%5E%7B+-+2%7D+%5D+%3D+%5B+%7BM%7D%5E%7BP%7D+%7Bl%7D%5E%7BQ%7D+%7Bt%7D%5E%7B+-+2Q%7D+%5D+%5C%5C+%5C%5C+)
» compare the exponent to similar term :-
then
=> P = 1 and Q = 1
So

» The proportionaliity constant K = 1 (From Experiment)
So
=> F = ma
_________[PROVED]
hence
=> Force directly proportional to m^P.a^Q
=> F directly proportional m^P.a^Q
» Substitute Dimension formula :-
» compare the exponent to similar term :-
then
=> P = 1 and Q = 1
So
» The proportionaliity constant K = 1 (From Experiment)
So
=> F = ma
_________[PROVED]
Deepsbhargav:
theku dear xD
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