Chemistry, asked by Raghav1111111111, 5 months ago

Explain the following:

(i)Ice is lighter than water

(ii) Be2 does not exist.

(iii)Bond order of N2 is greater than N2

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but the bon order of O2 is less than that of O2

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Answers

Answered by lavanyawankhede
1

Answer:

1 When water freezes, water molecules form a crystalline structure maintained by hydrogen bonding. Solid water, or ice, is less dense than liquid water. Ice is less dense than water because the orientation of hydrogen bonds causes molecules to push farther apart, which lowers the density

2 From the electronic configuration it is clear that there is no singly filled atomic orbital present in beryllium. Without the half filled orbital,the overlapping is not possible ,therefore Be2 molecule does not exist.

3 According to Molecular orbital theory: N2 have 6 more electrons in a bonding atomic orbital so it's bond order is 3, whereas N2+ has only 5 in bonding so it's bond order is 2.5. Bond dissociation energy is directly proportional to Bond order of a molecule so N2 has more bond dissociation energy.

Explanation:

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