Explain the following (Only Equation)
(a) Reaction of chlorine with Conc. NaOH
NH
(b) Chlorine with Excess of.
(c) Reaction of sodium hydroxide with hydrochloric acid
H,80. with Bleaching powder
(d) Reaction of
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Explanation:
Reaction of chlorine with-
(a) Cold and dilute NaOH:
When chlorine reacts with cold and dilute solution of sodium hydroxide the products obtained are Cl
−
+ClO
−
.
Cl
2
+
(Cold and dilute)
2NaOH
⟶NaCl+NaOClO
(b) Excess NaOH:
Chlorine reacts with excess ammonia to give ammonium chloride (NH
4
Cl) and Nitrogen gas.
3Cl
2
+
(Excess)
8NH
3
⟶6NH
4
Cl+N
2
(c) Ca(OH)
2
:
Dry slaked lime with chlorine is used to prepare bleaching powder.
Cl
2
+Ca(OH)
2
⟶CaOCl
2
+CaCl
2
+HCl
The mixture is known as bleaching powder.
(d) Na
2
S
2
O
3
:
Sodium thiosulfate react with chlorine and water to produce sulphur, hydrogen chloride and sodium sulphate.
Cl
2
+Na
2
S
2
O
3
⟶Na
2
SO
4
+HCl+S
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