Question

explain the following reaction by oxdation number method. Cu2+ + Zn ---> Zn2+ +Cu

Answer 1

CU 2 + zns o4 = zn2
+ CU s o4

Answer 2

ZnSO4(aq). Zn(s) + Cu2+(aq) net ionic: Zn2+(aq) + Cu(s) lost 2 e– gained 2 e– oxidation reduction. + 2 e–. + 2 e– oxidation reduction half reactions ............the you find