Chemistry, asked by kumarkrishna1886, 8 months ago

Explain the following statement-The magnetic and spectral properties of Lanthanides differ from those of '3d' and '4d' block elements.

Answers

Answered by sj4362860
0

Answer:

Lanthanides are the elements which constitute a distinct series of fourteen elements from

cerium (Ce, Z = 58) to lutetium (Lu, Z = 71). They are so called because these elements succeed

lanthanum (La, Z =57), the element of Group 3 and lie between it and hafnium (Hf, Z = 72),

the element of Group 4, both belonging to third transition series (or 5d-transition series). That

is why they are also known as inner transition elements. These fourteen elements belong to f-

block and are the members of 4f-series because the last or differentiating electron in the atoms

of these elements enters 4f-subshell, i.e., the f-subshell of ante-penultimate shell (here n=6).

Thus, f-block elements have partly filled f-subshells of (n-2)th shell in the elementary or ionic

state.

The first and the last elements of the 4f-series have been mentioned above (i.e., Ce and Lu).

The rest twelve elements along with their symbols and atomic numbers are given below:

praseodymium (Pr, Z = 59), neodymium (Nd, Z = 60), promethium (Pm, Z = 61), samarium

(Sm, Z = 62), europium (Eu, Z = 63), gadolinium (Gd, Z = 64), terbium (Tb, Z = 65),

dysprosium (Dy, Z = 66), holmium (Ho, Z = 67), erbium (Er, Z = 68), thulium (Tm, Z =69)

and ytterbium (Yb, Z = 70). In analogy with various series of d-block elements, these elements

are called first inner transition series elements. All the fourteen elements of the series resemble

closely in their electronic configuration and chemical properties with one another as well as

with lanthanum which may be called a prototype of lanthanide elements. All these elements

said to be the members of Group 3, i.e., Sc group and have been allotted one single position in

the periodic table.

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