explain the following using identity
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(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
here
a=√2 x, b= 2y ,c =-√3 z
substitute this values u will get the solution as
2x²+4y²+3z²+4√2xy-4√3yz-2√6xz
here
a=√2 x, b= 2y ,c =-√3 z
substitute this values u will get the solution as
2x²+4y²+3z²+4√2xy-4√3yz-2√6xz
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