Question

Explain the following with the help of balanced chemical equation:
a. Bleaching action of SO,
b. Dehydration of formic acid by concentrated H2SO4.
c.
Buming of benzene in presence of excess of dioxygen.​

Answer 1

Answer:

Explanation:

( a ) Bleaching Action of SO₂

Its bleaching action is due to reduction and is temporary

Sulphur dioxide acts as bleaching agent in the presence of water

SO₂ + 2H₂O ⇒ H₂SO₄ + 2 [ H ]

Coloured Matter + [ H ] ⇒ Colourless Matter

( b ) Dehydration of Formic acid by concentrated H₂SO₄

Sulphuric acid is a strong dehydrating agent. It dehydrates formic acid to give CO and water.

HCOOH + conc H₂SO₄ ⇒ CO + H₂O

( c ) Burning of benzene in presence of excess of dioxygen

Benzene often burns with a sooty flame, meaning that incomplete combustion has occurred

C₆H₆ + 15/2 O₂ ⇒ 6CO₂ + 3H₂O

Answer 2

❏ Question:-

@ Explain the following with the help of balanced chemical equation:

a. Bleaching action of SO,

b. Dehydration of formic acid by concentrated H2SO4.

c.Buming of benzene in presence of excess of dioxygen.

❏ Answer:-

✦Bleaching action of $SO_2$:-

• $SO_2$ acts as bleaching agent in presence of $H_2O$.

•Basically bleaching by $SO_2$ is a temporary cause atmospheric $O_2$ re-oxidized the bleached substenance or matter after some time.

Chemical reaction

$SO_2(g)+2H_2O\underset{}{\xrightarrow{ }}H_2SO_4(aq)+2[H]$

$2[H]+\red{colouring \: matter}\underset{}{\xrightarrow{ }}Colourless\:matter$

✦Dehydration of formic acid by concentrated $H_2SO_4$:-

•$H_2SO_4$ or sulphuric acid is a strong dehydrating agent .

• $H_2SO_4$ reacts with $HCOOH$ and produce CO and $H_2O$.

Chemical reaction

$HCOOH+H_2SO_4(con.)\:\longrightarrow\: CO+H_2O$

✦Buming of benzene or $(C_6H_6)$ in presence of excess of dioxygen.

•When $(C_6H_6)$ undergoes combustion in air , then carbon(C) and hydrogen(H) atoms combine with the molecules of $O_2$ and produce carbon dioxide ($CO_2$) and warer ($H_2O$).

Chemical reaction

$2C-6H_6+15O_2\:\longrightarrow\: 12CO_2+6H_2O$

━━━━━━━━━━━━━━━━━━━━━━━

$\underline{ \huge\mathfrak{hope \: this \: helps \: you}}$