explain the formation of BF3 molecule with SP2 hybridization
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BF3 has a boron atom with three outer-shell electrons in its ground state and three fluorine atoms containing seven outer electrons. ... In short, Boron needs 3 hybridized orbitals to make bonds with 3 atoms of F where the 2pz orbitals get overlapped with these hybridized sp2 orbitals and bonds are formed.
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