Explain the formation of Ethane molecule.
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Answered by
7
✌✌Hey, mate here is your answer⤵
BONDING IN ETHENE
Important! You will find this much easier to
understand if you first read the article about the
bonding in methane.
You may also find it useful to read the article on
orbitals if you aren't sure about simple orbital
theory.
Ethene, C 2H4
The simple view of the bonding in ethene
At a simple level, you will have drawn ethene
showing two bonds between the carbon atoms.
Each line in this diagram represents one pair of
shared electrons.
Ethene is actually much more interesting than
this.
An orbital view of the bonding in ethene
Ethene is built from hydrogen atoms (1s 1) and
carbon atoms (1s 22s 22p x 12p y 1).
The carbon atom doesn't have enough unpaired
electrons to form the required number of bonds,
so it needs to promote one of the 2s 2 pair into
the empty 2p z orbital. This is exactly the same
as happens whenever carbon forms bonds -
whatever else it ends up joined to.
So the first thing that happens is . . .
Promotion of an electron
There is only a small energy gap between the 2s
and 2p orbitals, and an electron is promoted from
the 2s to the empty 2p to give 4 unpaired
electrons. The extra energy released when these
electrons are used for bonding more than
compensates for the initial input.
Hope this answer will help you..《《
#Be Brainly#
@1Angel25
BONDING IN ETHENE
Important! You will find this much easier to
understand if you first read the article about the
bonding in methane.
You may also find it useful to read the article on
orbitals if you aren't sure about simple orbital
theory.
Ethene, C 2H4
The simple view of the bonding in ethene
At a simple level, you will have drawn ethene
showing two bonds between the carbon atoms.
Each line in this diagram represents one pair of
shared electrons.
Ethene is actually much more interesting than
this.
An orbital view of the bonding in ethene
Ethene is built from hydrogen atoms (1s 1) and
carbon atoms (1s 22s 22p x 12p y 1).
The carbon atom doesn't have enough unpaired
electrons to form the required number of bonds,
so it needs to promote one of the 2s 2 pair into
the empty 2p z orbital. This is exactly the same
as happens whenever carbon forms bonds -
whatever else it ends up joined to.
So the first thing that happens is . . .
Promotion of an electron
There is only a small energy gap between the 2s
and 2p orbitals, and an electron is promoted from
the 2s to the empty 2p to give 4 unpaired
electrons. The extra energy released when these
electrons are used for bonding more than
compensates for the initial input.
Hope this answer will help you..《《
#Be Brainly#
@1Angel25
Answered by
3
Formation of ethane (C2 H2) molecule:
(In ethane each of two carbon atoms shares one hydrogen atoms and two electrons between themsel Toon atoms shares one electron with each of the two ons between themselves) The Lewis dot structure. When two combining atoms share 3 electron pairs a triple bond is ectron pairs a triple bond is formed. Formation of ethyne (C2 H2) molecule In ethyne each of two carbon atoms share one electron with a hydrogen atom and 3 electrons between themselves forming triple bond between the two carbon atom.
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