Chemistry, asked by prathanamahesh25, 1 day ago

Explain the formation of ionic bond in sodium chloride with equation and electron transfers

Answers

Answered by ujjayinisom05
0

Explanation:

When sodium reacts with chlorine, it transfers its one outermost electron to the chlorine atom. By losing one electron, sodium atom forms a sodium ion (Na+) and by gaining one electron, the chlorine atom forms a chloride ion (Cl-). Sodium ion has positive charge whereas chloride ions have negative charge.

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Answered by ravindralokhande144
0

Answer:

Now, Na is in excess of one electron to attain octet configuration whereas chlorine is deficient of one electron. So, one electron of Na atom is transferred to Cl atom and thus an ionic bond is formed due to the transfer of electrons. Therefore, NaCl has Na+ and Cl− atoms

Explanation:

Sodium chloride is an ionic compound with the formula NaCl. So, basically sodium and chlorine respond together to generate a substance that is familiar to almost everybody known as sodium chloride or common salt. The reaction is as shown:

2Na(s)+Cl2(g)→2NaCl(s)

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