Explain the formation of solid and solve the question.
Class 10th CBSE!
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Hey☺⭐☺
As per the question,
Hypotenuse, AC =√3×3+4×4
= 5 cm
Area of ΔABC =1/2 * AB * AC
1/2 * AC * OB = 1/2* 4 * 3
OB = 12/5 = 2.4 cm
Volume of double cone = Volume of cone 1 + Volume of cone 2
1/3πr2h1 + 1/2πr2h2
1/3πr2 (h1 + h2)
1/3πr2 (OA + OC)
1/3 * 3.14 * (2.4)2 (5)
= 30.14 cm3
Surface area of double cone = Surface area of cone 1 + Surface area of cone 2
= πrl1 + πrl2
= πr [4 + 3]
= 3.14 * 2.4 * 7
= 52.75 cm2
Hope you like this ☺❣☺
As per the question,
Hypotenuse, AC =√3×3+4×4
= 5 cm
Area of ΔABC =1/2 * AB * AC
1/2 * AC * OB = 1/2* 4 * 3
OB = 12/5 = 2.4 cm
Volume of double cone = Volume of cone 1 + Volume of cone 2
1/3πr2h1 + 1/2πr2h2
1/3πr2 (h1 + h2)
1/3πr2 (OA + OC)
1/3 * 3.14 * (2.4)2 (5)
= 30.14 cm3
Surface area of double cone = Surface area of cone 1 + Surface area of cone 2
= πrl1 + πrl2
= πr [4 + 3]
= 3.14 * 2.4 * 7
= 52.75 cm2
Hope you like this ☺❣☺
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gaurav2013c:
Hey bro, please show, how you got the radius and H1 and H2
Answered by
2
hope this helps you☺☺. ☺☺☺
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