Question

Explain the formation of water molecule with the help of vsepr theory.

Answer 1

H2O

Central atom:OO contributes:6 e−2 x H contibute:2 e−Total VSE:8Total VSEP:4Geometry:V-shaped (based on tetrahedral)

Note

H–O–H bond angle = 104.5° (less than 109° due to lone-pair:bonding-pair repulsion being greater than bonding-pair:bonding-pair repulsion)

Answer 2

Answer:

• VSEPR theory is based on the fact/ assumption that there is a repulsion between the pairs of valence electrons in all atoms, and the atoms will always tend to arrange themselves in a manner in which this electron pair repulsion is minimalized.

• This arrangement of the atom determines the geometry of the resulting molecule.
• Atomic number of oxygen is 8. It has 6 valence electrons and requires 2 more for an octet configuration.
• Oxygen is the central atom in water molecule.
• Atomic number of hydrogen is 1 so it requires  1 electron to obtain valence configuration
• Therefore, two hydrogen atoms form 1 sigma bond (each) with the central oxygen atom.

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