Chemistry, asked by devsolanki854, 5 months ago

Explain the given reaction what happened when , BeCl2 is reduced with LiAlH4.

Answers

Answered by subhasmitapanda35

Answer:

so make it brainliest

Explanation:

The reaction of aluminum hydride with beryllium chloride in diethyl ether has been studied by infrared spectroscopy. The reaction proceeds according to the following equations: BeCl2 + AlH3 → H2AlCl + HBeCl; HBeCl + AlH3 ⇌ H2AlCl + BeH2. Hydridoberyllium chloride was prepared unequivocally by the reaction of BeH2 and BeCl2 and shown to be the product of the above reaction. When AlH3 is used in excess, BeH2 precipitates from solution. The yield of BeH2 depends on the amount of excess AlH3 used. Hydridoberyllium chloride is stable to disproportionation and is dimeric in ether solvent. Difinitive beryllium-hydrogen stretching and deformation frequencies are reported.

Answered by dipalpatel020387

Answer:

tata7aagagagagahahagagaghaahjajaabahahbabababb

Previous Question

Next Question

Similar questions

Math, 2 months ago

Plot the points A(5,0),B(5,2), C(5,6) and D(5,3) on a graph sheet. Verify if they lie on a line.

Hindi, 2 months ago

एक नगर में दो ष्स्त्रयााँ - एक ही बालक के सलए दािेदार – आपस में तकरार – मामला न्यायाधीश के पास – दोनों की बातें सुनना – न्याय करना – बालक के दो टुकड़े करके बााँट लो – एक स्त्री मौन – दसू री का रोना शुरू – बच्चे को न काटने की बबनती – न्याय – रोती हुई स्त्री को बालक देन story ...

Environmental Sciences, 2 months ago

गटात न बसणारा शब्द सांगा? भारत ,श्रीलंका,भूटान,म्यानमार...