Question

explain the greatest three digit number as a product of prime​

Answer 1

Let N be the three-digit number which has the greatest number of different factors. Since 2×3×5×7×11>1000, N at most has four different prime factors.

If N only has one prime factor, then N=29, and so N has 10 different factors.

If N has exactly two prime factors, then N=25×33, and so N has 24 different factors.

If N has exactly three prime factors, then N=24×32×5, and so N has 30 different factors.

If N has exactly four prime factors, then N=23×3×5×7, and so N has 32 different factors.

Thus, N=23×5×7=840.

hope it's helpful :-)))

Answer 2

the greatest three digit number is 999

then the product in prime numbers is

111×9

3×37×3×3