explain the Guass law for magnetic field
Answers
hope it helps you
mark me a brainlist
In physics, Gauss's law for magnetism is one of the four Maxwell's equations that underlie classical electrodynamics. It states that the magnetic field B has divergence equal to zero, in other words, that it is a solenoidal vector field. ... These forms are equivalent due to the divergence theorem
Hey mate,
Gauss law states that total flux enclosed by a gaussian surface is \dfrac{1}{Eo}
Eo 1 times the total charge.
ØE = q/Eo
Proof :-
ØE = \int{E.ds}∫E.ds
➝ ØE = \int{Eds cos{\theta}}∫Edscosθ
\thetaθ = 0°
Cos \thetaθ = 1
➝ ØE = \oint{Eds cos{\theta}}∮Edscosθ
➝ ØE = \oint{Eds}∮Eds
➝ ØE = E \oint{ds}∮ds
{E = Constant Electic Field}
➝ ØE = E. 4πr² .........(1)
E = \dfrac{1}{4{\pi{Eo}}} \dfrac{q}{r^2}
4πEo1r 2q ........(2)
Using 2 in 1,
➝ \dfrac{1}{4{\pi{Eo}}}4πEo1 \dfrac{q}{r^2} r 2q× 4πr²