Physics, asked by vaishalipatil0101197, 9 months ago

explain the Guass law for magnetic field​

Answers

Answered by A1231
2

hope it helps you

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In physics, Gauss's law for magnetism is one of the four Maxwell's equations that underlie classical electrodynamics. It states that the magnetic field B has divergence equal to zero, in other words, that it is a solenoidal vector field. ... These forms are equivalent due to the divergence theorem

Answered by s1266aakansha782696
0

Hey mate,

Gauss law states that total flux enclosed by a gaussian surface is \dfrac{1}{Eo}

Eo 1 times the total charge.

ØE = q/Eo

Proof :-

ØE = \int{E.ds}∫E.ds

➝ ØE = \int{Eds cos{\theta}}∫Edscosθ

\thetaθ = 0°

Cos \thetaθ = 1

➝ ØE = \oint{Eds cos{\theta}}∮Edscosθ

➝ ØE = \oint{Eds}∮Eds

➝ ØE = E \oint{ds}∮ds

{E = Constant Electic Field}

➝ ØE = E. 4πr² .........(1)

E = \dfrac{1}{4{\pi{Eo}}} \dfrac{q}{r^2}

4πEo1r 2q ........(2)

Using 2 in 1,

➝ \dfrac{1}{4{\pi{Eo}}}4πEo1 \dfrac{q}{r^2} r 2q× 4πr²

Hope it helps...

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