Question

Explain the Hybridisation of PCl5​

Answer 1

Answer:

The five orbitals viz 1s, 3p, and 1d orbitals are free for hybridization. Therefore, it can obtain a set of 5sp3d hybrid orbitals directed to the 5 corners of a trigonal bipyramidal (VSEPR theory). ... In PCl5 the 5sp3d orbitals of phosphorus overlap with p orbitals of chlorine atoms. The p orbitals are singly occupied.

Answer 2

Answer:

In PCl5 molecule the central atom is P

15P – 1s2,2s2,2p6,3s2,3p3

excited state  — 1s2,2s2,2p6,3s1, 3p3, 3d1

no.of singly occupied orbitals —>

 1  +  3  +  1 = 5

(s)    (p)    (d)              

so, it is sp3d Hybridisation.

Geometry of PCl5 molecule is trigonal bipyramidal. Bond angle is 90 and 120.